In Nuclear fission, when one neutron hits an atom why are more neutrons pushed out?
Im just a little confused..why when one neutron hits an atom, 3 neutrons are pushed out? why three and what causes it to push them out? im very confused! thnx!
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August 27th, 2010 at 4:02 am
the atom is out of ballance and breaks down, the amount depends on the original material and the result material
August 27th, 2010 at 4:34 am
Think of it like breaking off in a game of pool
August 27th, 2010 at 4:44 am
Hard to imagine this but try.The nucleus of an atom has to obey complicated rules about the ratio of neutrons to protons to be stable,think of unstable as being like a water drop very very near,but above boiling point.Such a nucleus would be the compound nucleus which forms when an extra proton merges with the nucleus of uranium 235.the compound nucleus to reduce the energy splits into two nearly equal parts and these two lighter nuclei cannot use all the neutrons;these neutrons are therefor free to carry on the splitting process with other atom of uranium 235.In the process enormous amounts of energy are liberated because the atoms formed are lighter in mass than the starting atoms,and the loss of mass is immediate converted into heat and radiation as predicted by the Einstein equation Energy = mass times(velocity of light times velocity of light).Incidentally the number of neutrons released is close to 3,it depends on which way the compound nucleus splits.